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2^(6-3x)=16^x+2)
We move all terms to the left:
2^(6-3x)-(16^x+2))=0
We add all the numbers together, and all the variables
2^(-3x+6)-(16^x+2))=0
We get rid of parentheses
2^(-3x+6)-16^x-2)=0
We add all the numbers together, and all the variables
2^(-3x+6)-16^x=0
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